A light bulb has a resistance of 210 ohms . It is connected to a standard wall socket (120 V rms, 60.0 Hz).
(a) Determine the rms current in the bulb.
I did this part and got a value of .571 Amps and its correct
(b) Determine the rms current in the bulb after a 10.0 µF capacitor is added in series in the circuit. (in amps)
(c) It is possible to return the current in the bulb to the value calculated in part (a) by adding an inductor in series with the bulb and the capacitor. What is the value of the inductance of this inductor? (in H)
RCL Circuits Physics?
Part "a", you are correct.
By how much the current would be reduced with the capacitor, I'm not sure. Based on the use of capacitors in line voltage chargers for batteries, you should only get about 40 Milli-amps through it. The inductor, if it is the right one, would form a series resonant circuit which would be a low dynamic resistance or a low reactance to the 120 volts AC, but you would not recover the 0.571 amps of a purely resistive circuit.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment